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You ll also notice that the joined up cursive form of the characters is visually quite different from their form when separated out individually. This is normal; the ultimate visual representation of the character in the string is entirely separate from the string itself. We re just so used to the characters of our own language that we don t tend to think of them as abstract symbols, and tend to discount any visual differences down to the choice of font or other typographical niceties when we are interpreting them. We could happily design a font where the character e looks like Q and the character f looks like A. All our text processing would continue as normal: searching and sorting would be just fine (words starting with f wouldn t start appearing in the dictionary before words starting with e), because the data in the string is unchanged; but when we drew it on the screen, it would look more than a bit confusing.* The take-home point is that there are a bunch of layers between the .NET runtime s representation of a string as data in memory, and its final visual appearance on a screen, in a file, or in another application (such as notepad.exe, for example). As we go through this chapter, we ll unpick those layers as we come across them, and point out some of the common pitfalls. Let s get on and see how the .NET Framework presents a string to us.

In our Photograph class, we would like two Photographs to be equal if they represent the same file So far, however, this will not be the case Since Photograph is a reference type, two objects will be equal only if they refer to the same physical storage on the heap It doesn t matter if both objects internally represent the same image file If they are different references, they are not equal This behavior should come as no surprise to the seasoned Java coders among us, but might seem a little strange to programmers accustomed to C++ or Visual Basic behavior..

Many-to-many If both sides of the relationship can have more than one object, the relationship is many-to-many. For example, an Item can be in more than one Category and a Category can have multiple Items.

Thread ExampleThread;

public static LocalResource uploadFolder = RoleEnvironment.GetLocalResource("FilesUploaded");

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<available> <uptodate> <os> <equals> <isset> <checksum> <http> <socket> <filesmatch> <contains> <istrue> <isfalse>

Tap the Weather icon. Unless you live in Cupertino, California, the default weather settings are not for your area. You will need to add your location. 1. 2. Touch the small i in the lower right-hand corner to go to the Weather settings screen. If the town selected is not one you wish to keep track of, just touch the red minus sign and you will be prompted to delete the location. See Figure 24 3.

<Border x:Name="LinksBorder" Style="{StaticResource LinksBorderStyle}"> <StackPanel x:Name="LinksStackPanel" Style="{StaticResource LinksStackPanelStyle}"> <HyperlinkButton x:Name="HomeLink" Style="{StaticResource LinkStyle}" NavigateUri="/Home" TargetName="ContentFrame" Content="home"/>

Such code doesn t really seem fair to the base class. I mean, it defined all the core requirements for derived classes, but it doesn t get any of the credit since it can t be directly instantiated. But there is a way for a base class to control its own destiny, to take all the glory for itself. It does this with the NotInheritable keyword.

Usually when AppleScript evaluates a literal reference, it immediately retrieves the value from the location: set my_rec to {name: "John", age: 18} set my_age to age of my_list --> 18 tell application "Finder" set the_disks to every disk end tell --> {startup disk of application "Finder", disk "Backup" of application "Finder"} Most of the time this is what you want, but occasionally it s useful to specify a reference at one point in a script without resolving the reference until later A common example where this happens automatically is AppleScript s repeat with..in.. loop, where the loop variable is assigned a reference to each list item in turn.

Under normal circumstances, you do not need to know the actual type of these instances; you can just talk to the object returned through its Encoding base class.

Let s imagine that this Firefighter class is being implemented by one of our colleagues. She tested the new implementation against her Firefighter unit test suite, exactly as required, and everything passed just fine fires were extinguished. Then she handed it over to us to use (with our new TraineeFirefighter class that we re working on). If we compile and run, we get the following output:

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